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NTCLE100E3103JB0
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NTCLE100E3103JB0数据手册
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NTCLE100E3
www.vishay.com
Vishay BCcomponents
Revision: 24-Aug-12
4
Document Number: 29049
For technical questions, contact: nlr@vishay.com
THIS DOCUMENT IS SUBJECT TO CHANGE WITHOUT NOTICE. THE PRODUCTS DESCRIBED HEREIN AND THIS DOCUMENT
ARE SUBJECT TO SPECIFIC DISCLAIMERS, SET FORTH AT www.vishay.com/doc?91000
R
T
VALUE AND TOLERANCE
These thermistors have a narrow tolerance on the B-value,
the result of which provides a very small tolerance on the
nominal resistance value over a wide temperature range. For
this reason the usual graphs of R = f(T) are replaced by
Resistance Values at Intermediate Temperatures Tables,
together with a formula to calculate the characteristics with
a high precision.
FORMULAE TO DETERMINE NOMINAL
RESISTANCE VALUES
The resistance values at intermediate temperatures, or the
operating temperature values, can be calculated using the
following interpolation laws (extended “Steinhart and Hart”):
where:
A, B, C, D, A
1
, B
1
, C
1
and D
1
are constant values
depending on the material concerned; see table below.
R
ref.
is the resistance value at a reference temperature (in
this event 25 °C, R
ref.
= R
25
).
T is the temperature in K.
Formulae numbered and are interchangeable with an
error of max. 0.005 °C in the range 25 °C to 125 °C and
max. 0.015 °C in the range - 40 °C to + 25 °C.
DETERMINATION OF THE
RESISTANCE/TEMPERATURE DEVIATION
FROM NOMINAL VALUE
The total resistance deviation is obtained by combining
the “R
25
-tolerance” and the “resistance deviation due to
B-tolerance”.
When:
X = R
25
-tolerance
Y = resistance deviation due to B-tolerance
Z = complete resistance deviation,
then: or Z X + Y
When:
TCR = temperature coefficient
T = temperature deviation,
then:
The temperature tolerances are plotted in the graphs on the
previous page.
Example: at 0 °C, assume X = 5 %, Y = 0.89 % and
TCR
= 5.08 %/K (see table ), then:
A NTC with a R
25
-value of 10 k has a value of 32.56 k
between - 1.17 °C and + 1.17 °C.
Notes
(1)
Temperature < 25 °C
(2)
Temperature 25 °C
R
T
R
ref
e
ABT CT
2
DT
3
++ +
=
(1)
T
R
= A
1
B
1
R
R
ref
----------ln C
1
ln
2 R
R
ref
----------
D
1
ln
3 R
R
ref
----------
+++


1
(2)
Z1
X
100
----------
+


1
Y
100
----------
+


1= 100 %
T
Z
TCR
------------
=
Z1
5
100
----------
+ 1
0.89
100
-----------
+ 1



100%=
T
Z
TCR
------------
5.93
5.08
-----------
1.167 C 1.17 C===
1.05 1.0089 1100 % 5.9345 %= ( 5.93 %)=
PARAMETER FOR DETERMINING NOMINAL RESISTANCE VALUES
NUMBER
B
25/85
(K)
NAME
TOL. B
(%)
A
B
(K)
C
(K
2
)
D
(K
3
)
A
1
B
1
(K
-1
)
C
1
(K
-2
)
D
1
(K
-3
)
1 2880
Mat O. with
Bn = 2880K
3 - 9.094 2251.74 229098 - 2.744820E+07 3.354016E-03 3.495020E-04 2.095959E-06 4.260615E-07
2 2990
Mat P. with
Bn = 3990K
3 - 10.2296 2887.62 132336 - 2.502510E+07 3.354016E-03 3.415560E-04 4.955455E-06 4.364236E-07
3 3041
Mat Q. with
Bn = 3041K
3 - 11.1334 3658.73 - 102895 5.166520E+05 3.354016E-03 3.349290E-04 3.683843E-06 7.050455E-07
4 3136
Mat R. with
Bn = 3136K
3 - 12.4493 4702.74 - 402687 3.196830E+07 3.354016E-03 3.243880E-04 2.658012E-06 - 2.701560E-07
5 3390
Mat S. with
Bn = 3390K
3 - 12.6814 4391.97 - 232807 1.509643E+07 3.354016E-03 2.993410E-04 2.135133E-06 - 5.672000E-09
6
3528
(1)
Mat I. with
Bn = 3528K
0.5
- 12.0596 3687.667 - 7617.13 - 5.914730E+06 3.354016E-03 2.909670E-04 1.632136E-06 7.192200E-08
3528
(2)
- 21.0704 11903.95 - 2504699 2.470338E+08 3.354016E-03 2.933908E-04 3.494314E-06 - 7.712690E-07
7 3560
Mat H. with
Bn = 3560K
1.5 - 13.0723 4190.574 - 47158.4 - 1.199256E+07 3.354016E-03 2.884193E-04 4.118032E-06 1.786790E-07
8 3740
Mat B. with
Bn = 3740K
2 - 13.8973 4557.725 - 98275 - 7.522357E+06 3.354016E-03 2.744032E-04 3.666944E-06 1.375492E-07
9 3977
Mat A. with
Bn =3977K
0.75 - 14.6337 4791.842 - 115334 - 3.730535E+06 3.354016E-03 2.569850E-04 2.620131E-06 6.383091E-08
10 4090
Mat C. with
Bn = 4090K
1.5 - 15.5322 5229.973 - 160451 - 5.414091E+06 3.354016E-03 2.519107E-04 3.510939E-06 1.105179E-07
11 4190
Mat D. with
Bn = 4190K
1.5 - 16.0349 5459.339 - 191141 - 3.328322E+06 3.354016E-03 2.460382E-04 3.405377E-06 1.034240E-07
12 4370
Mat E. with
Bn = 4370K
2.5 - 16.8717 5759.15 - 194267 - 6.869149E+06 3.354016E-03 2.367720E-04 3.585140E-06 1.255349E-07
13 4570
Mat F. with
Bn = 4570K
1.5 - 17.6439 6022.726 - 203157 - 7.183526E+06 3.354016E-03 2.264097E-04 3.278184E-06 1.097628E-07

NTCLE100E3103JB0 数据手册

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